Mysteryy

Great service. Bought 2m from him the other day and he delivered within minutes. ^_^

Is this issue resolved? I am going to lock the topic. If the issue is not resolved, please pm me so that I can reopen this topic. We can then try to get this issue fixed if it still persist. ^_^

Topic moved to the correct section. I hate to see you go, I hope you still visit every now and then. ^_^

Somebody had to do it. l0l

So you build a graph based on those loaded regions? What about the graph, did you use an edge weighted graph or what? And how did you store it, in a serialized file? :P

Looks pretty good. How did you get the cached obstacle data? Did you walk around auto generate the graph using the loaded regions?

Wut, people actually got unbanned for tweeting jagex?

Well, we had a Nintendo NES. I still have that bad boy, works like a charm l0l. Also had sega genesis, super nintendo, N64. I think the first console that was actually mine was a ps1 though. The others were my dads. ^_^

I am looking to buy 2m 07 gp. I am also wanting to get some starter items. My main got banned a while back, so I am trying to start up a new account. Some started items I need are things like Games necklaces, Rings of dueling, a few glories, some low level gear, etc. If you are willing to sell post here, or feel free to pm me. I need to know your price per mill, as well as how much you want for the items you have to sell me. I will also buy the 2m alone, and collect the items my self if I must. :P I will go first if I deem you trusted, otherwise you go first. ^_^

So what you are saying is that the script you are trying to make is not showing up? You need to use .java not .groovy You also need to make sure that your compile output path is in the /OSBot/scripts folder Let me know if you need more help. ^_^

It was a delayed ban. Last time that you were botting they caught you, and when you logged in this time they banned you. Jagex does this to maximize the ban time. that way when you log in and actually want to play, the ban starts.

Well if your asking if I have a dream career, it would be working for Intel or Nvidia. I want to be more on the hardware design side, hence the reason that I picked computer engineering, not software engineering or CS. But I highly doubt that I will ever make it there. xD

Oh haha, I was like how is this difficult xD Yea I am computer engineering, if I cant prove some of these things then I dont deserve to graduate. l0l

As difficult as this? I took courses that covered this stuff a like 2 or 3 years ago. :P What is your major?

Cool cool. Are you currently in uni?

Yea I totally forgot about google ads haha

amg I was wondering the same thing. Like does jagex pay you guys to ad for rs? l0l Oh, google ads makes sense. xD

We could always add 5 more recent topics for those members that don't have the rank to view top 5 online. ^_^

You say that you are sure that you did not get hacked, how can you be sure? It is a possibility, unfortunately.

I am sorry I am at work so its hard to reply to your questions. For number 8 consider this: (n+1)! = n! * (n+1) now rewrite that expression as ((n!) * (n + 1) / n!) - n You can then cancel out the top n! with the bottom n! leaving us with: n + 1 - n from there its obvious that the answer is just 1 Ok now that I have time to answer your second question, a variable to a negative power is 1/variable^positive power eg: v^-2 = 1/(v^2) Using that you first add up all exponents, resulting in the condensed expression: r^(2+2/3) * t^(-1) = r^(8/3) * (1/t) = (r^(8/3)) / t If I am unclear or said something stupid I apoligize, I am standing up outside in 100 degree heat on a computer at work l0l It is quite difficult to make proofs in these conditions xD

Have you tried multiplying the top and bottom by the recipricol of the bottom? I am not sure how much knowledge you have, or if you know what that is. Also I am at work so its kind of hard for me to help out because I cant give you a ton of details. Try to multiply the top and bottom by (x-2)/(x-3) Doing this will probably give you some like terms, which you can then cancel out on the top and bottom, resulting in one of the answers. This is how you get (a fraction)/(a fraction) into a single fraction.

Some people just want to watch the world burn... xD

So what is your question? ^_^

Hmm maybe someone will see this and have an idea for you. I will try to see if I can think of anything else. ^_^