Math Challenge # 1 - 100k winner

[Diamonds]

Winner = ohhungry

Who ever answers this math question and explains why completely how they did it, they win 100k. 

Rules - Solve it

 

 

 

1. Which of the following expressions is a factor of 4x^2 - 8x + 3?

 

a. 2x + 1 

b. 4x + 3

c. 2x - 3

d. 2x + 3

 

Goodluck, dont forget to explain how you solved it, who ever answers more detailed will win the prize. Contest will end in 2 hours.

Edited August 10, 2013 by Diamonds

[Nalizzle]

xx

Edited August 10, 2013 by Nalizzle

[Gildarts]

 

Try this:

(2x____)(2x____) 

Last times last has to be 3*1 or 1*3, and in this case, it doesn't really matter what order you use.

 

(2x+3)(2x+1) 

Notice that the outer times outer and inner times inner give you 2x + 6x = 8x, which is the correct middle term. 

Final answer: (2x+3)(x+1) 

 

 

SO, your answer would be D) 2x+3

 

http://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/Polynomials-and-rational-expressions.faq.question.88198.html

inb4 shitstorm

[ScorpioZ]

(2x-3)(2x-1)

 

foil it out

 

=

 

4x^2-2x-6x+3

 

simplified =

 

4x^2-8x+3

 

 

therefor c)

Edited August 10, 2013 by ScorpioZ

[Diamonds]

 

xx

 

close, retry ur calculations and check ur formula

[Occazn]

FK U

Edited August 10, 2013 by Occazn

[Diamonds]

FK U

try again :P

[ohhungry]

4x^2-8x+3

 

to find roots, use quadratic formula

 

x=(8(+/-)sqrt(8^2-4(4)(3))/8)

  =(8(+/-)sqrt(16))/8

  =(8(+/-)4)/8

  =3/2 and 1/2

 

Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct

 

a)2x+1= 0 (does not work for either value of x)

b)4x+3 = 0 (does not work for either value of x)

c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3

d)2x+3 = 0 (does not work for either value of x)

 

Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C

 

Sidenote: You should probably choose harder math problems :P

Edited August 10, 2013 by ohhungry

[Diamonds]

4x^2-8x+3

 

to find roots, use quadratic formula

 

x=(8(+/-)sqrt(8^2-4(4)(3))/8)

  =(8(+/-)sqrt(16))/8

  =(8(+/-)4)/8

  =3/2 and 1/2

 

Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct

 

a)2x+1= 0 (does not work for either value of x)

b)4x+3 = 0 (does not work for either value of x)

c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3

d)2x+3 = 0 (does not work for either value of x)

 

Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C

 

Sidenote: You should probably choose harder math problems

ahha nope sorry try again, note: ^ means exponent

[mdanhorn]

(2x-3)(2x-1)

 

foil it out

 

=

 

4x^2-2x-6x+3

 

simplified =

 

4x^2-8x+3

 

 

therefor c)

Edited August 10, 2013 by mdanhorn

[Mr Asshole]

(2x-3)(2x-1)

 

adding explanation -

 

take factors of the a and c term you get:

4 = 2 x 2 or 1 x 4

3 = 1 x 3

 

because the equation follows this form ax2 - bx + c then

 

the numbers are arranged in this fashion  (x - h)(x - k)

 

we try the various options

 

(2x-1)(2x-3)

(1x-1)(4x-3)

 

the one that gives us the right answer is (2x-3)(2x-1)

 

Edited August 10, 2013 by Exarticus

[Illumi]

Change title to "Need Maths Homework Done - Paying 100K"

[ohhungry]

 

4x^2-8x+3

 

to find roots, use quadratic formula

 

x=(8(+/-)sqrt(8^2-4(4)(3))/8)

  =(8(+/-)sqrt(16))/8

  =(8(+/-)4)/8

  =3/2 and 1/2

 

Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct

 

a)2x+1= 0 (does not work for either value of x)

b)4x+3 = 0 (does not work for either value of x)

c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3

d)2x+3 = 0 (does not work for either value of x)

 

Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C

 

Sidenote: You should probably choose harder math problems

ahha nope sorry try again, note: ^ means exponent

 

Uhh...yeah, my answer's right. unless by 4x^2 you actually meant (4x)^2, in which case there are no real roots.

[Diamonds]

Change title to "Need Maths Homework Done - Paying 100K"

not really, have an answer , ( will be doing multiple challenges for people in need of small money )

[mdanhorn]

 

4x^2-8x+3

 

to find roots, use quadratic formula

 

x=(8(+/-)sqrt(8^2-4(4)(3))/8)

  =(8(+/-)sqrt(16))/8

  =(8(+/-)4)/8

  =3/2 and 1/2

 

Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct

 

a)2x+1= 0 (does not work for either value of x)

b)4x+3 = 0 (does not work for either value of x)

c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3

d)2x+3 = 0 (does not work for either value of x)

 

Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C

 

Sidenote: You should probably choose harder math problems

ahha nope sorry try again, note: ^ means exponent

 

 

He's actually right...

 

and he did it in a manner much harder then it needed to be.