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Botre

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Everything posted by Botre

  1. Botre

    Question

    "Easy-made" is hard to objectify since you can make anything relatively complex. If you want to make free scripts, I suggest you find something without a direct premium counterpart, there are still plenty of untouched niches. The script market is tough as it is, having to compete with free is fighting a lost battle.
  2. Heads or tails? package org.bjornkrols.fun; import java.util.Random; /** * @author Bjorn Krols (Botre) * @version 0.0 * @since April 16, 2015 */ public class Coin { public static void main(String[] args) { Coin coin = new Coin(); coin.toss(); if (coin.isHeads() || coin.isTails()) System.out.println(":doge:"); } private static final Random RANDOM = new Random(); private boolean heads; public Coin() { toss(); } public void toss() { heads = RANDOM.nextBoolean(); } public boolean isHeads() { return heads; } public boolean isTails() { return !heads; } } I'm bored
  3. Not super useful for scripting, but here you go. package org.bjornkrols.math; import java.util.BitSet; /** * @author Bjorn Krols (Botre) * @version 0.2 * @since April 16, 2015 */ public final class SieveOfEratosthenes { public static void main(String[] args) { SieveOfEratosthenes sieve = new SieveOfEratosthenes(100); System.out.println(sieve.isPrime(29)); } public BitSet sieve; public SieveOfEratosthenes(int n) { calculate(n); } private void calculate(int n) { sieve = new BitSet(n); // Assume all numbers are prime. for (int i = 2; i < sieve.size(); i++) sieve.set(i, true); // Find the square root of n. double sqrtn = Math.floor(Math.sqrt(n)); for (int i = 2; i < sqrtn; i++) if (sieve.get(i)) for (int j = i * i; j < n; j += i) sieve.set(j, false); } public boolean isPrime(int n) { return sieve.get(n); } } package org.bjornkrols.math; /** * @author Bjorn Krols (Botre) * @version 0.0 * @since April 16, 2015 */ public final class PrimalityTest { private PrimalityTest() { // This class should never be instantiated. // Do not delete or make accessible. } public static boolean test(long n) { // A whole number greater than one is called a prime number if its only positive divisors (factors) are one and itself. // All whole numbers between 1 and 3 are prime. if (n <= 3) return n > 1; // All multiples of 2 and 3 are not prime. if (n % 2 == 0 || n % 3 == 0) return false; // Find the square root of n. double sqrtn = Math.floor(Math.sqrt(n)); // All primes are of the form 6k ± 1 (with the exception of 2 and 3). for (int divisor = 5; divisor <= sqrtn; divisor += 6) if (n % divisor == 0 || n % (divisor + 2) == 0) return false; return true; } } 2 true 3 true 5 true 7 true 11 true 13 true 17 true 19 true 23 true 29 true 31 true 37 true 41 true 43 true 47 true 53 true 59 true 61 true 67 true 71 true 73 true 79 true 83 true 89 true 97 true
  4. I'm pretty sure that's a tuba :p
  5. A bit bright, especially the white text on light blue. Other than that it looks neato.
  6. How's 80k/h better than chinning ? :x
  7. Enjoy amigo! (I'll be supervising the super mods, as per your request )
  8. Very unlikely so don't worry. Give it some more time
  9. It's going to get you flagged. But then again, a super click intensive task will probably too. Let us know how it turns out ^^
  10. If a script was updated by its writer then it can take a couple of hours for the update to be visible to its users. What kind of update are you waiting for ?
  11. Are you talking about local scripts or SDN scripts? Have you tried the "refresh" button?
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