Give me a minute for 10, just gotta find paper. I swear i had some paper lying aaround
Ok it's answer B :
The amout of feet traveled between first and 6th bounce (so not counting before and after those two) is 2/3h + 2/3*(2/3h)+2/3*(2/3*2/3h)+ etc... (5 times) this gives:
2/3h+(2/3)^2*h+(2/3)^3*h+(2/3)^4*h+(2/3)^5*h which is basically a sum in the form of answer B