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What section on OSBot is a good section to ask math questions from members?


Goku1

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So what is your question? happy.png

Y0E3g5z.png

 

 

 

Have you tried multiplying the top and bottom by the recipricol of the bottom? I am not sure how much knowledge you have, or if you know what that is. Also I am at work so its kind of hard for me to help out because I cant give you a ton of details. tongue.png

 

Try to multiply the top and bottom by (x-2)/(x-3)

 

 

Doing this will probably give you some like terms, which you can then cancel out on the top and bottom, resulting in one of the answers.

 

This is how you get (a fraction)/(a fraction) into a single fraction.

Edited by Mysteryy
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Have you tried multiplying the top and bottom by the recipricol of the bottom? I am not sure how much knowledge you have, or if you know what that is. Also I am at work so its kind of hard for me to help out because I cant give you a ton of details. tongue.png

 

Try to multiply the top and bottom by (x-2)/(x-3)

 

 

Doing this will probably give you some like terms, which you can then cancel out on the top and bottom, resulting in one of the answers.

 

This is how you get (a fraction)/(a fraction) into a single fraction.

This helped me out, thanks and good luck in work.

 

I have another set of questions if anyone else can help with:

bf71ac4cc5.png

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This helped me out, thanks and good luck in work.

 

I have another set of questions if anyone else can help with:

bf71ac4cc5.png

 

I am sorry I am at work so its hard to reply to your questions. For number 8 consider this:

 

(n+1)! = n! * (n+1)

now rewrite that expression as

 

((n!) * (n + 1) / n!) - n

 

You can then cancel out the top n! with the bottom n! leaving us with:

n + 1 - n

from there its obvious that the answer is just 1

 

happy.png

 

 

Ok now that I have time to answer your second question, a variable to a negative power is 1/variable^positive power

 

eg: v^-2 = 1/(v^2)

 

Using that you first add up all exponents, resulting in the condensed expression:

r^(2+2/3) * t^(-1)

 

= r^(8/3) * (1/t)

 

= (r^(8/3)) / t

 

 

If I am unclear or said something stupid I apoligize, I am standing up outside in 100 degree heat on a computer at work l0l

 

It is quite difficult to make proofs in these conditions xD

Edited by Mysteryy
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