Diamonds Posted August 10, 2013 Posted August 10, 2013 (edited) Winner = ohhungry Who ever answers this math question and explains why completely how they did it, they win 100k. Rules - Solve it 1. Which of the following expressions is a factor of 4x^2 - 8x + 3? a. 2x + 1 b. 4x + 3 c. 2x - 3 d. 2x + 3 Goodluck, dont forget to explain how you solved it, who ever answers more detailed will win the prize. Contest will end in 2 hours. Edited August 10, 2013 by Diamonds
Nalizzle Posted August 10, 2013 Posted August 10, 2013 (edited) xx Edited August 10, 2013 by Nalizzle
Gildarts Posted August 10, 2013 Posted August 10, 2013 Try this:(2x____)(2x____) Last times last has to be 3*1 or 1*3, and in this case, it doesn't really matter what order you use. (2x+3)(2x+1) Notice that the outer times outer and inner times inner give you 2x + 6x = 8x, which is the correct middle term. Final answer: (2x+3)(x+1) SO, your answer would be D) 2x+3 http://www.algebra.com/algebra/homework/Polynomials-and-rational-expressions/Polynomials-and-rational-expressions.faq.question.88198.html inb4 shitstorm
ScorpioZ Posted August 10, 2013 Posted August 10, 2013 (edited) (2x-3)(2x-1) foil it out = 4x^2-2x-6x+3 simplified = 4x^2-8x+3 therefor c) Edited August 10, 2013 by ScorpioZ 1
Diamonds Posted August 10, 2013 Author Posted August 10, 2013 xx close, retry ur calculations and check ur formula
ohhungry Posted August 10, 2013 Posted August 10, 2013 (edited) 4x^2-8x+3 to find roots, use quadratic formula x=(8(+/-)sqrt(8^2-4(4)(3))/8) =(8(+/-)sqrt(16))/8 =(8(+/-)4)/8 =3/2 and 1/2 Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct a)2x+1= 0 (does not work for either value of x) b)4x+3 = 0 (does not work for either value of x) c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3 d)2x+3 = 0 (does not work for either value of x) Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C Sidenote: You should probably choose harder math problems :P Edited August 10, 2013 by ohhungry
Diamonds Posted August 10, 2013 Author Posted August 10, 2013 4x^2-8x+3 to find roots, use quadratic formula x=(8(+/-)sqrt(8^2-4(4)(3))/8) =(8(+/-)sqrt(16))/8 =(8(+/-)4)/8 =3/2 and 1/2 Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct a)2x+1= 0 (does not work for either value of x) b)4x+3 = 0 (does not work for either value of x) c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3 d)2x+3 = 0 (does not work for either value of x) Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C Sidenote: You should probably choose harder math problems ahha nope sorry try again, note: ^ means exponent
mdanhorn Posted August 10, 2013 Posted August 10, 2013 (edited) (2x-3)(2x-1) foil it out = 4x^2-2x-6x+3 simplified = 4x^2-8x+3 therefor c) Edited August 10, 2013 by mdanhorn
Mr Asshole Posted August 10, 2013 Posted August 10, 2013 (edited) (2x-3)(2x-1) adding explanation - take factors of the a and c term you get: 4 = 2 x 2 or 1 x 4 3 = 1 x 3 because the equation follows this form ax2 - bx + c then the numbers are arranged in this fashion (x - h)(x - k) we try the various options (2x-1)(2x-3) (1x-1)(4x-3) the one that gives us the right answer is (2x-3)(2x-1) Edited August 10, 2013 by Exarticus
Illumi Posted August 10, 2013 Posted August 10, 2013 Change title to "Need Maths Homework Done - Paying 100K"
ohhungry Posted August 10, 2013 Posted August 10, 2013 4x^2-8x+3 to find roots, use quadratic formula x=(8(+/-)sqrt(8^2-4(4)(3))/8) =(8(+/-)sqrt(16))/8 =(8(+/-)4)/8 =3/2 and 1/2 Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct a)2x+1= 0 (does not work for either value of x) b)4x+3 = 0 (does not work for either value of x) c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3 d)2x+3 = 0 (does not work for either value of x) Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C Sidenote: You should probably choose harder math problems ahha nope sorry try again, note: ^ means exponent Uhh...yeah, my answer's right. unless by 4x^2 you actually meant (4x)^2, in which case there are no real roots.
Diamonds Posted August 10, 2013 Author Posted August 10, 2013 Change title to "Need Maths Homework Done - Paying 100K" not really, have an answer , ( will be doing multiple challenges for people in need of small money )
mdanhorn Posted August 10, 2013 Posted August 10, 2013 4x^2-8x+3 to find roots, use quadratic formula x=(8(+/-)sqrt(8^2-4(4)(3))/8) =(8(+/-)sqrt(16))/8 =(8(+/-)4)/8 =3/2 and 1/2 Set all options equal to 0 and sub in either value of x, whichever statements hold true are correct a)2x+1= 0 (does not work for either value of x) b)4x+3 = 0 (does not work for either value of x) c)2x-3 = 0 (work for x=3/2, therefore this is a factor of 4x^2-8x+3 d)2x+3 = 0 (does not work for either value of x) Therefore 2x-3 is a factor of 4x^2-8x+3, the answer is C Sidenote: You should probably choose harder math problems ahha nope sorry try again, note: ^ means exponent He's actually right... and he did it in a manner much harder then it needed to be.
