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0000 to 9999 combination


Joseph

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Lol @ those calculations, - - - -, four digits, ten possibilities for each digit: 10*10*10*10=10.000. I don't know where you went to school..

Tbh my logic is easier than yours. So I don't know why your trash talking it. I could ask you the same thing, what school did you go to, but I really don't care.

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Tbh my logic is easier than yours. So I don't know why your trash talking it. I could ask you the same thing, what school did you go to, but I really don't care.

Okay

 

XX - YYY - XX

 

X for letters, Y for numbers. I'm using 22 different letters and 9 different numbers. How many combinations are possible XX-YYY-XX? Apply your logic please.

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nerds

Wise over ignorance. Is how I like to see it.

Okay

 

XX - YYY - XX

 

X for letters, Y for numbers. I'm using 22 different letters and 9 different numbers. How many combinations are possible XX-YYY-XX? Apply your logic please.

TOUCHÉ. That's where your logic comes in. Which now I know
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Lol @ those calculations, - - - -, four digits, ten possibilities for each digit: 10*10*10*10=10.000. I don't know where you went to school..

Okay

 

XX - YYY - XX

 

X for letters, Y for numbers. I'm using 22 different letters and 9 different numbers. How many combinations are possible XX-YYY-XX? Apply your logic please.

 

Since you're trashtalking Joseph, I want to ask you this:

 

From 0 to 2000, how many even numbers are there? Would you seriously use combinatorial logic for this?

 

Joseph's solution is by far the simplest for the type of problem he's talking about.

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Since you're trashtalking Joseph, I want to ask you this:

 

From 0 to 2000, how many even numbers are there? Would you seriously use combinatorial logic for this?

 

Joseph's solution is by far the simplest for the type of problem he's talking about.

1001.

My logic:

From 1-2000 there are 2000 combos.

There are only 1000 even combos within the 2000.

Finally 0 is an even number so we carry it over.

= 1001

Ok I see but what does Tom have to do with any of this?

he said the answer was 9999 and I'm saying no it is 10 000. That's all.
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1001.

My logic:

From 1-2000 there are 2000 combos.

There are only 1000 even combos within the 2000.

Finally 0 is an even number so we carry it over.

= 1001

he said the answer was 9999 and I'm saying no it is 10 000. That's all.

I see...

 

Although I was primarily asking for two digit numbers not 4 digits.

I guess that's just one of his many semi-annoying attempts to make a joke of my threads.

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1001.

My logic:

From 1-2000 there are 2000 combos.

There are only 1000 even combos within the 2000.

Finally 0 is an even number so we carry it over.

= 1001

he said the answer was 9999 and I'm saying no it is 10 000. That's all.

 

The reason people think it's 9999 over 10000 is because we start to count at 1, not 0. This is why programming is hard for a lot of people, especially with arrays, because they try to access index 1 as if it's index 0.

Things would be a lot easier if we started counting from 0, not 1.

 

My logic for 0000-9999 would be 10^4.

Where 4 is the max number of digits, and 10 since we're working in base 10. (you can have a maximum of 10 different states per digit in base 10; 0-9)

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