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Need help: Questions number 10 and 11 from College Algebra CLEP Study Guide


Goku1

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I'm not looking for answers. I'm just looking for someone to show me, step by step, how to solve these two College Algebra math problems.

 

The math problems are listed in the link below:

http://puu.sh/aEyK5/80505d273c.png

 

I tried inserting 2/3h with h = 6, but what confuses me is that strange symbol in one of the answer keys for question 1.

 

And for question 2 I assumed that because the line was on the x-axis, then the answer had to be q because no other line was on the x-axis.

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I'm not looking for answers. I'm just looking for someone to show me, step by step, how to solve these two College Algebra math problems.

The math problems are listed in the link below:

http://puu.sh/aEyK5/80505d273c.png

I tried inserting 2/3h with h = 6, but what confuses me is that strange symbol in one of the answer keys for question 1.

And for question 2 I assumed that because the line was on the x-axis, then the answer had to be q because no other line was on the x-axis.

I'm on my phone so I can explain number 1, but for the second question just know that anytime you have a line that is x = some number, it will be a vertical line on the x axis at that number. There are two lines on the x axis, not one. There is one at -3 and one a 3. Since its x = 3, not x =-3, you should be able to pick the correct one. ^_^

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I'm on my phone so I can explain number 1, but for the second question just know that anytime you have a line that is x = some number, it will be a vertical line on the x axis at that number. There are two lines on the x axis, not one. There is one at -3 and one a 3. Since its x = 3, not x =-3, you should be able to pick the correct one. happy.png

I see. How about the times where x would equal something like x=y+1. How do you find the line for that one?

Edited by Goku1
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I see. How about the times where x would equal something like x=y+1. How do you find the line for that one?

 

You can either leave it like that, or change it to the more widely used form that would be y = x-1. 

Then you can graph out a few points and you will see what the line would look like. So just start with x = 0, then y is -1. When x = 2, then y is 1, you can see the pattern and graph more points based on that. ^_^

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I see. How about the times where x would equal something like x=y+1. How do you find the line for that one?

Remeber the format y=mx+b

For a question like that solve for y which is y=x-1

The "m" which is the number in front of the x is the slope.

That -1 is the point on the y axis so it's (0,-1).

Plot your point, and use your slope to graph.

And for the first question idk lol

Edited by josedpay
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Give me a minute for 10, just gotta find paper. I swear i had some paper lying aaround


Ok it's answer B :

The amout of feet traveled between first and 6th bounce (so not counting before and after those two) is 2/3h + 2/3*(2/3h)+2/3*(2/3*2/3h)+ etc... (5 times) this gives:

2/3h+(2/3)^2*h+(2/3)^3*h+(2/3)^4*h+(2/3)^5*h which is basically a sum in the form of answer B

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