Goku1 Posted August 5, 2014 Posted August 5, 2014 I'm not looking for answers. I'm just looking for someone to show me, step by step, how to solve these two College Algebra math problems. The math problems are listed in the link below: http://puu.sh/aEyK5/80505d273c.png I tried inserting 2/3h with h = 6, but what confuses me is that strange symbol in one of the answer keys for question 1. And for question 2 I assumed that because the line was on the x-axis, then the answer had to be q because no other line was on the x-axis.
Mysteryy Posted August 5, 2014 Posted August 5, 2014 I'm not looking for answers. I'm just looking for someone to show me, step by step, how to solve these two College Algebra math problems. The math problems are listed in the link below: http://puu.sh/aEyK5/80505d273c.png I tried inserting 2/3h with h = 6, but what confuses me is that strange symbol in one of the answer keys for question 1. And for question 2 I assumed that because the line was on the x-axis, then the answer had to be q because no other line was on the x-axis. I'm on my phone so I can explain number 1, but for the second question just know that anytime you have a line that is x = some number, it will be a vertical line on the x axis at that number. There are two lines on the x axis, not one. There is one at -3 and one a 3. Since its x = 3, not x =-3, you should be able to pick the correct one. ^_^ 1
Goku1 Posted August 5, 2014 Author Posted August 5, 2014 (edited) I'm on my phone so I can explain number 1, but for the second question just know that anytime you have a line that is x = some number, it will be a vertical line on the x axis at that number. There are two lines on the x axis, not one. There is one at -3 and one a 3. Since its x = 3, not x =-3, you should be able to pick the correct one. I see. How about the times where x would equal something like x=y+1. How do you find the line for that one? Edited August 5, 2014 by Goku1
Arctic Posted August 5, 2014 Posted August 5, 2014 I see. How about the times where x would equal something like x=y+1. How do you find the line for that one? Transpose and solve for 'y'.
Mysteryy Posted August 5, 2014 Posted August 5, 2014 I see. How about the times where x would equal something like x=y+1. How do you find the line for that one? You can either leave it like that, or change it to the more widely used form that would be y = x-1. Then you can graph out a few points and you will see what the line would look like. So just start with x = 0, then y is -1. When x = 2, then y is 1, you can see the pattern and graph more points based on that. ^_^ 1
Joseph Posted August 5, 2014 Posted August 5, 2014 (edited) I see. How about the times where x would equal something like x=y+1. How do you find the line for that one?Remeber the format y=mx+bFor a question like that solve for y which is y=x-1 The "m" which is the number in front of the x is the slope. That -1 is the point on the y axis so it's (0,-1). Plot your point, and use your slope to graph. And for the first question idk lol Edited August 5, 2014 by josedpay 1
Goku1 Posted August 5, 2014 Author Posted August 5, 2014 I see. I understand the second question now. Any help with the first question?
theov Posted August 6, 2014 Posted August 6, 2014 Your name is Goku.... you shouldnt need to ask people l0l
thepecher Posted August 6, 2014 Posted August 6, 2014 Give me a minute for 10, just gotta find paper. I swear i had some paper lying aaround Ok it's answer B : The amout of feet traveled between first and 6th bounce (so not counting before and after those two) is 2/3h + 2/3*(2/3h)+2/3*(2/3*2/3h)+ etc... (5 times) this gives: 2/3h+(2/3)^2*h+(2/3)^3*h+(2/3)^4*h+(2/3)^5*h which is basically a sum in the form of answer B 1
Preliator Posted August 6, 2014 Posted August 6, 2014 The answer is actually A, not B. After bouncing i times, the ball reaches a *height* of h(2/3)^i. However, it travels 2h(2/3)^i (twice the height) before reaching the ground again, since the ball travels up and down. 2
thepecher Posted August 6, 2014 Posted August 6, 2014 The answer is actually A, not B. After bouncing i times, the ball reaches a *height* of h(2/3)^i. However, it travels 2h(2/3)^i (twice the height) before reaching the ground again, since the ball travels up and down. True, nice catch there
Goku1 Posted August 12, 2014 Author Posted August 12, 2014 The answer is actually A, not B. After bouncing i times, the ball reaches a *height* of h(2/3)^i. However, it travels 2h(2/3)^i (twice the height) before reaching the ground again, since the ball travels up and down. What does sideway "M" and the number 5 represent? for the answer "A"?
Mysteryy Posted August 12, 2014 Posted August 12, 2014 What does sideway "M" and the number 5 represent? for the answer "A"? That symbol is Sigma in the greek alphabet. It means "The sum of (2H) * (2/3)^i " from i = 1, to i = 5. In other words it means: ((2H) * (2/3)^1) + ((2H) * (2/3)^2) + ((2H) * (2/3)^3) + ((2H) * (2/3)^4) + ((2H) * (2/3)^5)