Somebody explain how to solve this convergent series and I'll give you 200k 07.

 

http://www.wolframalpha.com/input/?i=sum+%28%284i-2%29*n%29%2F%282%5Ei%29+i+from+1+to+infinity

 

Go!!!!

 

Edit: So umm, if anybody actually wants to know the answer. Here's how:

 

Sum((4i - 2)n/2^i) = nSum((4i - 2)/2^i) = nSum(4(i-1/2)2^(-i)) = nSum((2 + 4(i-1/2))2^(-i)) =

(Using arithmetico geometric series and taking the limit as n goes to infinity) n(2/(1-2) + 4(2)/(1-2)^2) = n(-2 + 8) = 6n

Edited January 25, 201412 yr by ohhungry

I clicked on it, and looked at. And was like i dont know. And then closed it with disappointment.

I clicked on it, and looked at. And was like i dont know. And then closed it with disappointment.

 

Not worth the 200k. We can negotiate ;).

Hey it's 33 man. 200k please

What grade is that from ?? Or what classes are you taking ? 

The answer is infinity.

opened, closed.