Not too sure how this would be done , some assistance would be nice osb2 btw

See Swizz's answer.

Edited June 1, 201411 yr by Eliot

One basic way to do it (not update proof) is to simply check that position for the ID of the open door, there are better ways to do this, but this is the most basic (that I can think of).

No ID required, use the name of the door.

 

Just search for the doors containing w/e the name of the door is, then check if any of the positions of those doors are in the open position.

Edited June 1, 201411 yr by Deffiliate

No ID required, use the name of the door.

 

Just search for the doors containing w/e the name of the door is, then check if any of the positions of those doors are in the open position.

How do you know if the door is open or closed?

lol you guys make this so complex:

Arrays.asList(door.getDefinition().getActions()).contains("Close")

 

lol you guys make this so complex:

Arrays.asList(door.getDefinition().getActions()).contains("Close")

Yes, do it this way.

No ID required, use the name of the door.

 

Just search for the doors containing w/e the name of the door is, then check if any of the positions of those doors are in the open position.

worked like a charm thanks

You can also check the orientation.

But Swizz's option is probably the best.