why dont you do it to see the outcome ;)

Mathemetically speaking, yes it is possible. You can model the infinite coin tossing using a probability space with sample space Omega = {0,1}^N, where X_i = 0 means that the i'th toss is tails and 1 represents heads. In this model, tossing heads every time is equivalent to the event x = (1,1,1,...). Since x is in Omega, x is by definition a possible outcome.

 

However, it's very easy to prove that P(X=x)=0, i.e. the probabilty of you tossing heads every time is 0. Equivalently, it is almost surely that you will toss heads at least once.

 

If you are interested in this subject, look up measure/probability theory on wikipedia .

 

If a coin is tossed an infinite amount of times, is it possible for it to land on heads every flip for infinity? 

Or must it eventually succumb to infinity, and land on tails?

 

 

I wish i had the time to ponder over such things

 

TL;DR: The probability of getting heads again approaches 0 as you flip the coin more times. If you flip it infinitely many times, the probability becomes 0, because that's how math works.

 

Did you never do parabolas in math class?

 

f(x) = 1/x

 

It approaches 0, but never touches 0.

 

The probability never becomes 0, because the 1 stays as a 1, not a 0.

 

The chances of it landing on tails is almost surely, but not certainly.

 

 

TL;DR: The probability of getting heads again approaches 0 as you flip the coin more times. If you flip it infinitely many times, the probability becomes 0, because that's how math works.

 

Did you never do parabolas in math class?

 

f(x) = 1/x

 

It approaches 0, but never touches 0.

 

The probability never becomes 0, because the 1 stays as a 1, not a 0.

 

The chances of it landing on tails is almost surely, but not certainly.

 

but f(0) = 1/0. math is broken.

 

 

TL;DR: The probability of getting heads again approaches 0 as you flip the coin more times. If you flip it infinitely many times, the probability becomes 0, because that's how math works.

 

Did you never do parabolas in math class?

 

f(x) = 1/x

 

It approaches 0, but never touches 0.

 

The probability never becomes 0, because the 1 stays as a 1, not a 0.

 

The chances of it landing on tails is almost surely, but not certainly.

 

It also never reaches infinity. If it were to "reach" infinity, it would also reach 0. The question assumes reaching infinity is possible (or it must be assumed to be a limit), either way my answer is correct.

It's impossible, the average person lives for 2,524,608,000 seconds, you do not have enough time to reach infinity. If you somehow managed to live forever, then after unveiling the mystery of immortality you somehow managed to flip heads successfully over and over, you would have to repeat this forever, because infinity is forever.

 

There is a 50% chance you will land on heads. There is is a 50% chance you will land on tails. There is 50% chance in every flip you make.

Edited November 2, 201312 yr by Redfire

 

Lets do a little math (or atleast I'll make up some math, and hope it makes sense)

 

What's the chance of flipping heads once in a row? 1/2

What's the chance of flipping heads twice in a row? 1/4

What's the chance of flipping heads three times in a row? 1/8

What's the chance of flipping heads four times in a row? 1/16

 

As you can see, this follows a simple pattern of 1/2^n

 

We can express this as a product series where x_i = 1/2. For those of you unfamiliar with a product series, here is a picture http://gyazo.com/a5cd47e6f6244c345f0c4213378242d4

 

A product series is denoted by a pi symbol with a lower bound below the pi symbol, denoted by i, and an upper bound above the pi symbol, denoted by n. This is followed by an argument x_i, which in our case is 1/2.

 

If we are flipping a coin infinite times, our product series will go from i=0 to n=infinity. Which is basically just (1/2)*(1/2)*(1/2)...over and over again infinitely many times.

 

The limit of this series (i.e, the number which it converges to) is 0, because any number divided by infinity = 0. 

Therefore the probability of flipping a coin and it landing on heads infinitely many times is exactly 0.

 

Note: You cannot actually divide by infinity, I added this just for simplicity. Instead of dividing by infinity, you would take the limit of 1/x as x goes to infinity. For those who do not yet know what limits are, basically if x becomes really really really really big, what number does 1/x tend towards?

 

TL;DR: The probability of getting heads again approaches 0 as you flip the coin more times. If you flip it infinitely many times, the probability becomes 0, because that's how math works.

 

I am sorry, but you cannot divide by infinity, because infinity is not a number, it is a concept.

 

 

This is true. Also, the number would be infinitesimally close to zero, but it would not equal "exactly zero."

If any process in the universe could be repeated an infinite number of time, logic would apply.

As it stands, good luck.

Also, Mountain Goats

f(0) = 1/0

x = 0 is a vertical asymptote, a value where as x gets closer y gets either higher or lower without bound, but x may never equal 0

Edited November 3, 201312 yr by nseguin42

ANything in life is possible.

Possible, nearly infinite improbable. 

possible but improbable

I swear all logic is lost...

Since its being flipped infinitely it will never stop flipping, therefor the answer will never come

But to enlighten the situation if a coin is flipped infinitely amount of times

there will be a infinite amount of heads flipped and a infinite amount of tails flipped of the same size

Edited November 4, 201312 yr by LifezHatred

The answer is no.

 

It will eventually land on tails, you don't need to be a genius to figure it out either, the answer lays within the coin.

The answer is no.

 

It will eventually land on tails, you don't need to be a genius to figure it out either, the answer lays within the coin.

 

The answer is actually yes