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1 + 1 = 0

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1 + 1

= 1 + √1

= 1 + √[(-1)(-1)]

= 1 + √(-1)√(-1)

= 1 + i^2

= 1 + (-1)

= 1 - 1

= 0

 

For those wondering:

 

Step 3 to step 4 is based on the theorem √ab = √a√b

 

Step 4 - 6:

 

√(-1) = i, so √(-1)√(-1) is i^2

 

but, i^2 is also (-1) so 1 + i^2 = 1 + (-1)

You cant substitute in two negative variables when you already have a constant integer... dry.png

  • Author

You cant substitute in two negative variables when you already have a constant integer... dry.png

 

yes, you can

 

You cant substitute in two negative variables when you already have a constant integer... dry.png

 

yes, you can

 

 

Only Batman can do such a feat ...

1 + 1

= 1 + √1

= 1 + √[(-1)(-1)]

= 1 + √(-1)√(-1)

= 1 + i^2

= 1 + (-1)

= 1 - 1

= 0

 

For those wondering:

 

Step 3 to step 4 is based on the theorem √ab = √a√b

 

Step 4 - 6:

 

√(-1) = i, so √(-1)√(-1) is i^2

 

but, i^2 is also (-1) so 1 + i^2 = 1 + (-1)

 

 

√ab = √a√b does not apply in this particular case. √[(-1)(-1)] does not, and never will be the same as √(-1)√(-1).

 

Therefor the validity of anything you say, is in the garbage. Before you go off making up theorems make sure your math is correct. ^.^

 

10xao0m.png

 

And if you doubt the correctness of this, your ignorance is the beyond help of anybody. 

 

 

You cant substitute in two negative variables when you already have a constant integer... dry.png

 

yes, you can

 

 

Only Batman can do such a feat ...

 

And Superman.

  • Author

Ok, Mysteryy, I made a mistake, you do not have to be a complete jackass...

Ok, Mysteryy, I made a mistake, you do not have to be a complete jackass...

You didn't make a mistake, you copy pasted a mistake. I've seen that trick numerous times before.

Ok, Mysteryy, I made a mistake, you do not have to be a complete jackass...

  

Just sayin, you could use Google before you go off thinking you invented new math.

Ok, Mysteryy, I made a mistake, you do not have to be a complete jackass...

You didn't make a mistake, you copy pasted a mistake. I've seen that trick numerous times before.

^

so if i add 1 cookie to another cookie, both cookies dissapear? must be cookie monster who is behind this!

 

but seriously, 1+1=2. 

Edited by battie

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