http://prntscr.com/3plc9p

 

please help!

 

I got more questions when this is over

Angles EFG and EDG are right angles because the lines are tangential to the circles. Use pythagorean theorem to find missing side. There's my hint

 

At least I think. Not quite sure lol.

Edited June 4, 201411 yr by boizero

7

It's not 7.

 

The answer is 97 mate (:

Since EG is an external tangent of the circle G, we know that the angle EDG is 90 degrees. So, apply pythagoras theorem on the triangle EDG to find that the length ED = sqrt(EG^2 - GD^2) = sqrt(1600) = 40. Furthermore, by symmetry you have DC = FA = 55. Hence EC = ED + DC = 40 + 55 = 95.

Another one! Thank you by the way

Since EG is an external tangent of the circle G, we know that the angle EDG is 90 degrees. So, apply pythagoras theorem on the triangle EDG to find that the length ED = sqrt(EG^2 - GD^2) = sqrt(1600) = 40. Furthermore, by symmetry you have DC = FA = 55. Hence EC = ED + DC = 40 + 55 = 95.

 

Yeah that right. did my shit wrong lol

1x pythagoras theorem

1x addition

=95

http://prntscr.com/3pltks

I don't see the point of you asking for help on a skill mastery test.

I don't see the point of you asking for help on a skill mastery test.

The point is that I'm in summer school, and once I get these done I'm out.

http://prntscr.com/3pltks

 

Dude, that's EXACTLY the same excercise as the first one, just numbers are different...

 

EDIT:

 

1) Find out the length of AF throught Pythagoras theorem.

2) Add up the result of 1) with FE (26) and you got your solution.

Edited June 4, 201411 yr by blabla123